DNA Dilution Calculator
Enter DNA concentrations (ug/ul) for up to 10 samples and specify the final volume (ul) to calculate dilution volumes.
Sample (ug/ul) | DNA (ul) | DW (ul) |
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Enter DNA concentrations (ug/ul) for up to 10 samples and specify the final volume (ul) to calculate dilution volumes.
Sample (ug/ul) | DNA (ul) | DW (ul) |
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New to chemistry and lab work? Understanding concentration measurements and solution units is essential for success. In this beginner's guide, we'll simplify these concepts, making them accessible and practical for your experiments. Join us as we explore the basics and equip you with the knowledge to excel in your scientific journey.
: Molar concentration represents the number of moles (M) of solute present in 1 liter of solution. It is calculated as the ratio of the number of moles to the volume of the solution in liters.
"grams (g) = molecular weight × M (molar concentration) × L (volume)"
Example 1: If you want to prepare a 1 M NaCl solution with a volume of 1 liter, you can calculate the amount of NaCl needed as follows:
First, consider the molecular weight of NaCl, which is 58.44 g/mol.
Take into account the desired molar concentration, which is 1 M (1 mol/L).
The required amount of NaCl is calculated as follows:
Required NaCl (g) = Molecular Weight (g/mol) × Molar Concentration (mol/L) × Volume (L)
Required NaCl (g) = 58.44 g/mol × 1 mol/L × 1 L
Performing the calculation yields a required amount of 58.44 g of NaCl.
So, to prepare a 1 M NaCl solution with a volume of 1 liter, you would need 58.44 grams of NaCl.
EasyTools - Solution Dilution Calculator
: Normality is the equivalent weight of a solute (in grams) per liter of solution. An equivalent is the amount of a substance that can either gain or lose one mole of electrons in a chemical reaction. It is used primarily in acid-base reactions.
"grams (g) = molecular weight / valence × N (normality) × L (volume)"
Example 1: If you want to prepare 1 L of a 1 N AgNO3 solution, the required amount of AgNO3 in grams can be calculated as follows:
Molecular weight of AgNO3 = 170
Valence = 1
Using the formula: grams (g) = molecular weight / valence × N (normality) × L (volume)
X g = 170/1 x 1 x 1 = 170 g
Therefore, by dissolving 170 grams of AgNO3 in 1 L of water, you'll obtain a 1 N AgNO3 solution.
When the valence is "1," the Molarity (M) and Normality (N) concentrations are the same.
: Percentage concentration expresses the amount of solute as a percentage of the total solution weight or volume.
- Weight/Weight (% w/w): The weight of solute in grams per 100 grams of solution.
- Volume/Volume (% v/v): The volume of solute in milliliters per 100 milliliters of solution.
- Weight/Volume (% w/v): The weight of solute in grams per 100 milliliters of solution.
- Volume/Weight (% v/w): The volume of solute in milliliters per 100 grams of solution.
: Parts per million is a unit for expressing very low concentrations. It represents the number of milligrams (mg) of solute per liter of solution.
Note: ppm stands for "parts per million," indicating one part in a million, or 1/1,000,000.
Concentration Unit | Calculation Method | |
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Molar Concentration (M) | Moles of solute / Volume (liters) = mol/L | |
Normality (N) | Equivalent weight of solute (g) / Volume (liters) = N | N = M * Equivalent Factor* |
Percentage (% w/w) | Mass of solute (g) / Total mass of solution (g) x 100 = % w/w | |
Percentage (% v/v) | Volume of solute (mL) / Total volume of solution (mL) x 100 = % v/v | |
Percentage (% w/v) | Mass of solute (g) / Total volume of solution (mL) x 100 = % w/v | |
Percentage (% v/w) | Volume of solute (mL) / Total mass of solution (g) x 100 = % v/w | |
Parts Per Million (ppm) | Mass of solute (mg) / Total volume of solution (liters) = ppm | ppm = 1000 * M (mg/L) |
*Equivalent Factor (Normality - N)
: In chemistry, the Equivalent Factor, also known as Equivalent Weight, plays a vital role in normality (N) calculations. It represents the weight of a substance that can either gain or lose one mole of electrons or react with one mole of hydrogen ions (H⁺) in a chemical reaction.
Here's a simplified explanation of Equivalent Factors:
This concept is particularly valuable in normality (N) calculations, where it ensures that the concentration of substances in a solution is measured in equivalents per liter, accounting for their specific reactivity in chemical reactions. This knowledge is essential for accurate titrations and understanding the behavior of substances in various chemical processes.
1. Enter the concentration of each sample in the "Sample Concentrations (ug/mL)" section. You can leave some fields empty.
2. Input the common dilution factor and final sample volume.
3. Click the "Calculate Dilution" button to perform the calculation.
4. View the calculation results in the table. The sample with the lowest corrected concentration will be highlighted.
5. The required loading volumes for 50ug, 30ug, and 10ug of protein will be displayed.
Sample | Original Concentration (ug/mL) |
Protein (ug/uL) |
Lysate (uL) |
Lysis Buffer (uL) |
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Enter the following information and click the "Calculate" button to determine the drug volume to administer:
Result: 0
Enter the weight of the chemical, molecular weight, and the desired concentration to calculate the required solution volume.
The solution dilution calculator calculates the volume of stock concentrate to add to achieve a specified volume and concentration. It uses the formula M1V1 = M2V2, where "1" represents the concentrated conditions (i.e., stock solution molarity and volume), and "2" represents the diluted conditions (i.e., desired volume and molarity).
This simple calculator allows users to input RNA concentrations in ug/ul, and it calculates the amount of RNA needed for cDNA synthesis as well as the required volume of DW (distilled water). It can calculate the volume of reagents needed for cDNA synthesis and enables the download of both the entered RNA concentrations and the calculated RNA values.
Sample | RNA Amount for cDNA (ul) | DW Volume (ul) |
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